Integrand size = 16, antiderivative size = 52 \[ \int x \sqrt {3-2 x-x^2} \, dx=-\frac {1}{2} (1+x) \sqrt {3-2 x-x^2}-\frac {1}{3} \left (3-2 x-x^2\right )^{3/2}+2 \arcsin \left (\frac {1}{2} (-1-x)\right ) \]
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Time = 0.01 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {654, 626, 633, 222} \[ \int x \sqrt {3-2 x-x^2} \, dx=2 \arcsin \left (\frac {1}{2} (-x-1)\right )-\frac {1}{3} \left (-x^2-2 x+3\right )^{3/2}-\frac {1}{2} (x+1) \sqrt {-x^2-2 x+3} \]
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Rule 222
Rule 626
Rule 633
Rule 654
Rubi steps \begin{align*} \text {integral}& = -\frac {1}{3} \left (3-2 x-x^2\right )^{3/2}-\int \sqrt {3-2 x-x^2} \, dx \\ & = -\frac {1}{2} (1+x) \sqrt {3-2 x-x^2}-\frac {1}{3} \left (3-2 x-x^2\right )^{3/2}-2 \int \frac {1}{\sqrt {3-2 x-x^2}} \, dx \\ & = -\frac {1}{2} (1+x) \sqrt {3-2 x-x^2}-\frac {1}{3} \left (3-2 x-x^2\right )^{3/2}+\frac {1}{2} \text {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^2}{16}}} \, dx,x,-2-2 x\right ) \\ & = -\frac {1}{2} (1+x) \sqrt {3-2 x-x^2}-\frac {1}{3} \left (3-2 x-x^2\right )^{3/2}+2 \sin ^{-1}\left (\frac {1}{2} (-1-x)\right ) \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.96 \[ \int x \sqrt {3-2 x-x^2} \, dx=\frac {1}{6} \sqrt {3-2 x-x^2} \left (-9+x+2 x^2\right )+4 \arctan \left (\frac {\sqrt {3-2 x-x^2}}{3+x}\right ) \]
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Time = 0.23 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.77
method | result | size |
risch | \(-\frac {\left (2 x^{2}+x -9\right ) \left (x^{2}+2 x -3\right )}{6 \sqrt {-x^{2}-2 x +3}}-2 \arcsin \left (\frac {1}{2}+\frac {x}{2}\right )\) | \(40\) |
default | \(-\frac {\left (-x^{2}-2 x +3\right )^{\frac {3}{2}}}{3}+\frac {\left (-2-2 x \right ) \sqrt {-x^{2}-2 x +3}}{4}-2 \arcsin \left (\frac {1}{2}+\frac {x}{2}\right )\) | \(43\) |
trager | \(\left (\frac {1}{3} x^{2}+\frac {1}{6} x -\frac {3}{2}\right ) \sqrt {-x^{2}-2 x +3}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x +\sqrt {-x^{2}-2 x +3}+\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )\right )\) | \(61\) |
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Time = 0.27 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00 \[ \int x \sqrt {3-2 x-x^2} \, dx=\frac {1}{6} \, {\left (2 \, x^{2} + x - 9\right )} \sqrt {-x^{2} - 2 \, x + 3} + 2 \, \arctan \left (\frac {\sqrt {-x^{2} - 2 \, x + 3} {\left (x + 1\right )}}{x^{2} + 2 \, x - 3}\right ) \]
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Time = 0.29 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.62 \[ \int x \sqrt {3-2 x-x^2} \, dx=\sqrt {- x^{2} - 2 x + 3} \left (\frac {x^{2}}{3} + \frac {x}{6} - \frac {3}{2}\right ) - 2 \operatorname {asin}{\left (\frac {x}{2} + \frac {1}{2} \right )} \]
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Time = 0.28 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00 \[ \int x \sqrt {3-2 x-x^2} \, dx=-\frac {1}{3} \, {\left (-x^{2} - 2 \, x + 3\right )}^{\frac {3}{2}} - \frac {1}{2} \, \sqrt {-x^{2} - 2 \, x + 3} x - \frac {1}{2} \, \sqrt {-x^{2} - 2 \, x + 3} + 2 \, \arcsin \left (-\frac {1}{2} \, x - \frac {1}{2}\right ) \]
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Time = 0.27 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.62 \[ \int x \sqrt {3-2 x-x^2} \, dx=\frac {1}{6} \, {\left ({\left (2 \, x + 1\right )} x - 9\right )} \sqrt {-x^{2} - 2 \, x + 3} - 2 \, \arcsin \left (\frac {1}{2} \, x + \frac {1}{2}\right ) \]
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Time = 0.07 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.90 \[ \int x \sqrt {3-2 x-x^2} \, dx=\frac {\sqrt {-x^2-2\,x+3}\,\left (8\,x^2+4\,x-36\right )}{24}+\ln \left (x+1-\sqrt {-x^2-2\,x+3}\,1{}\mathrm {i}\right )\,2{}\mathrm {i} \]
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